A = ∫[0,2] (x^2 + 2x - 3) dx = [(1/3)x^3 + x^2 - 3x] from 0 to 2 = (1/3)(2)^3 + (2)^2 - 3(2) - 0 = 8/3 + 4 - 6 = 2/3
Solution:
Also, I need to clarify that providing a full solution manual may infringe on the copyright of the book. If you're a student or a professional looking for a solution manual, I recommend checking with the publisher or the author to see if they provide an official solution manual. A = ∫[0,2] (x^2 + 2x - 3)
3.2 Evaluate the line integral:
from t = 0 to t = 1.
f(x, y, z) = x^2 + y^2 + z^2
y = Ce^(3x)
∫(2x^2 + 3x - 1) dx = (2/3)x^3 + (3/2)x^2 - x + C